Magnitude of Friction Force - Circular Motion

AI Thread Summary
To determine the magnitude of the friction force required for a car of mass 1164 kg traveling at 10.8 m/s around a 288 m radius corner, the key is to calculate the centripetal acceleration. The centripetal acceleration can be found using the formula a = v²/r, resulting in an acceleration of approximately 0.41 m/s². The friction force, which provides this acceleration, can then be calculated using F = ma, yielding a friction force of about 474 N. Understanding that friction is the only force acting to maintain circular motion is crucial for solving this problem. This approach simplifies the process without needing the coefficient of friction.
Chica1975
Messages
63
Reaction score
0

Homework Statement


A car of mass 1164kg was traveling around a 288m radius corner at a speed of 10.8m/s. What was the magnitude of the fiction force required to maintain the vehicles path?


Homework Equations


F=ma
I have no idea after that


The Attempt at a Solution


I found mg = 11407.20

Can someone please explain about frictional force, I find this very hard, I have read and reread a lot of info but I just don't get it. Especially when I have to apply it to problems and I don't have the coefficient.

I am really stuck, please help!
 
Physics news on Phys.org
You don't need to know anything about friction to solve this. You just need to know the acceleration of the car, which is in circular motion with constant speed.
The only force that can cause this acceleration is the friction force.
 
Thanks but I still have no idea how to tackle this. Can someone please help me.
 
Anyone?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Friction direction change in a inclined circular bend (car on a road)
Replies
11
Views
1K
Direction of static friction between a vehicle and circular dome
Replies
9
Views
2K
A problem from a physics national competition
Replies
13
Views
1K
Car turning and centripetal force
Replies
18
Views
2K
Acceleration in uniform circular motion is uniform or non-uniform?
2
Replies
55
Views
3K
How can we model a rolling truck on an incline using rotational motion analysis?
Replies
24
Views
2K
For the friction formula when to use Fn(normal force)×mu and when F×mu
Replies
17
Views
2K
Friction Coefficients: Determining Force Direction?
Replies
6
Views
1K
A Car on a Banked Curve Moving in Uniform Circular Motion
Replies
7
Views
3K
Direction of friction in circular motion
Replies
5
Views
3K

Hot Threads

Recent Insights

Back
Top