How Do You Calculate the Magnetic Field in a Cylindrical Conductor?

AI Thread Summary
To calculate the magnetic field in a hollow cylindrical conductor carrying a uniformly distributed current I, the expression for the magnetic field in the region between the inner radius a and outer radius b is derived using Ampère's Law. The magnetic field B can be expressed as B = (μ₀ I)/(2πr), where r is the radial distance from the center of the cylinder. The current density j is defined as j = I/(π(b² - a²)). By applying Ampère's Law, the relationship B(r) * 2πr = μ₀ * j * π(r² - a²) is established, allowing for the calculation of B in the specified region. The discussion highlights the importance of understanding current direction and density in deriving the magnetic field. Overall, the derivation process emphasizes the application of fundamental electromagnetic principles.
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Problem said:
A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, uniformly distributed over its cross section.

Question said:
Derive an expression for the magnitude of the magnetic field in the region a < r < b.

I understand that it needs to relate to the following equation but that is it. B=\frac{\mu_{0} I}{2\Pi r}

I am unsure how to derive an answer for this, I am drawing a blank on solving this. Can anyone give me any helpful hints?
 
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what is the direction of the current? post the whole question pls...
 
That is the full question, the current is running through a hollow cylinder. From how I understand the current is flowing through direction of the hieght of the cylinder.
 
find the \ver{A} first, then B
 
\oint{\vec{B}\vec{dl}}=\mu_0\int{\int_S{j}}ds
and from this you can simply derive

B(r)2\pi r=\mu_0 j \cdot \pi(r^2-a^2)

where
j=\frac{I}{\pi (b^2-a^2)}.
 
Thanks to both of you. Clive you pointed out a part in which I made an error in my thinking of my previous answer. Appreciate the help.
 
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