Magnitude of moment about axis (Space Truss)

AI Thread Summary
To determine the moment of force F about axis CA in the tripod ABCD, the user suggests calculating the unit vector UCA and the moment MCA using the position vector rDC. However, there is uncertainty regarding the accuracy of the position vector rCA. A response indicates that the user’s rCA calculation is incorrect, highlighting that point A is 1.5 m on the y-axis and point C is 2 m on the x-axis. Accurate vector calculations are essential for solving the moment about the specified axis.
U1021981
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Homework Statement



Determine the magnitude of the moment of the force F about the axis CA of the tripod
ABCD, if F = {40i -30j -100k}N.

Image attached.

2. The attempt at a solution

Based on a similar question I found in the textbook my method to solve this question:

Find UCA = rCA/rCA = (-2/√8)i + (2/√8)j

Find MCA = UCA.(rDC?? * F)

However, I am unsure if the finding the position vector rDC is correct?

Am I going about this the right way?

Please help.

Thanks,

Tim
 

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U1021981 said:

Homework Statement



Determine the magnitude of the moment of the force F about the axis CA of the tripod
ABCD, if F = {40i -30j -100k}N.

Image attached.

2. The attempt at a solution

Based on a similar question I found in the textbook my method to solve this question:

Find UCA = rCA/rCA = (-2/√8)i + (2/√8)j

Find MCA = UCA.(rDC?? * F)

However, I am unsure if the finding the position vector rDC is correct?

Am I going about this the right way?

Please help.

Thanks,

Tim
Here's your image:

attachment.php?attachmentid=50244&d=1346128205.jpg


First of all your rCA must be incorrect. Look closely. Point A is 1.5 m from the origin on the y-axis. Point C is 2 M from the origin on the x-axis.
 
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