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A cannon sends a projectile towards a target a distance 1250m away. The initial velocity makes an angle 40 degrees with the horizontal. The target is hit.

What is the magnitude of the initial velocity?

How high is the highest point of the trajectory?

How long does it take for the projectile to reach the target?

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I tried to find the time by using the following formula:

t = sqrt (2d/g)

and then I used

x = x(initial) +v(initial)t + 1/2gt^2

and I get a decimal answer...

And then I took the distance and divided it by 2 ad I got 625 and did tan40 = h/625 but when i entered in the answer, it's wrong.

For the 3rd Q, I used the time that I found earlier from the formula, but that's incorrect too.

Any help would be appreciated.