Making CO2 Gas Concentrations: 50ppm, 100ppm, 1000ppm

  • Thread starter Thread starter strokebow
  • Start date Start date
  • Tags Tags
    Concentration Gas
AI Thread Summary
To create specific CO2 concentrations like 50ppm, 100ppm, and 1000ppm from a 99.999% CO2 gas cylinder, a dilution method is necessary. Users can mix CO2 with an inert gas such as argon or nitrogen to achieve the desired concentrations. Controlling the release of CO2 can be done using flow meters or gas regulators to ensure accurate mixing ratios. The discussion highlights the lack of readily available procedures online for such gas dilution practices. Practical advice and methods for achieving low gas concentrations are sought by users in various fields.
strokebow
Messages
122
Reaction score
0
Hi,

I have a gas cylinder 99.999% CO2.

I want to apply the CO2 to my sample at different concentration. e.g.) 50ppm, 100ppm, 1000ppm.

How do I make these concentrations of CO2 from my gas cylinder? Any practical advice would be truly appreciated.

cheers
 
Physics news on Phys.org
Mixed with what? Those first two concentrations are lower than the concentration of CO2 in air...
 
Hi

thanks for replying.

I don't know what to mix with.

For example, if I wanted to make up a solution of a liquid or powder to low concentration I would just dissolve in deionized water of the correct amounts to give the desired conc.

But for gases I am not sure.

What gas to mix with? I don't know?

To get 10ppm of CO2 how would this be done? Would you mix CO2 with argon? How can you control the amount you release?

I can't find a procedure for this on the internet altough I would expect this would be common practise in some fields?

Any ideas?
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks
Back
Top