- #36

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- 5,785

This is not correct. The gas in cylinder 2 did not undergo an adiabatic reversible compression. There was irreversibility in the connecting tube and valve between cylinder 1 and cylinder 2, and it was mixed with cooler gas from cylinder 1. $$(401.7)(290.5s)+(35.4)T_{2,f}=(410.5 + 26.6)(293)$$erobz said:$$T_{2,f}=T_i\left(\frac{P_{2,f}}{P_{2,i}}\right)^{\frac{\gamma-1}{\gamma}}=293\left(\frac{1.5}{1}\right)^{\frac{0.4}{1.4}}=328.9~\rm{K}$$

$$T_{2,f}=321.4\ K$$