Making discontinues function, continues.

  • Thread starter Thread starter burak100
  • Start date Start date
  • Tags Tags
    Function
burak100
Messages
33
Reaction score
0
making discontinues function, continues.!

Homework Statement



Given a function g, which is not continuous everywhere and g is increasing. The problem is how to approach to this function to make it continuous.

Homework Equations





The Attempt at a Solution



I am not sure but one way maybe using average value but the problem is; to use the average value, g should be continuous.
 
Physics news on Phys.org
burak100 said:
to use the average value, g should be continuous.
Says who? We can certainly form a function ##h## by averaging ##g## over a small neighborhood of each point:
$$h(x) = \int_{x - \epsilon}^{x+\epsilon} g(y) dy$$
Since ##g## is increasing, it can only have jump discontinuities, and at most countably many of them (proof?). Therefore, the Riemann integral is well defined at every ##x##. It's straightforward to show that ##h## is continuous everywhere (proof?).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top