Manipulating the PV=nRT Equation for Helium Balloon Volume

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The discussion revolves around calculating the remaining helium in a balloon after a change in pressure and volume, using the ideal gas law equation PV=nRT. The initial conditions include 20 grams of helium at 1000 torr, which changes to 900 torr and half the original volume. The user converted grams to moles and attempted to equate the initial and final states using the equation PV/n = PV/n. Feedback suggests improving notation and clarity in representing initial and final conditions, while also advising against overusing the term "approximate" when a precise answer is available. The final calculation indicates approximately 9 grams of helium remain in the balloon.
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Homework Statement


A balloon initially contains 20 grams of helium at a pressure of 1000 torr. After some helium is let out of the balloon the new pressure is 900 torr, and the volume is half of what it was. If the temperature has not changed, how much helium is now in the balloon?

Homework Equations


PV=nRT

The Attempt at a Solution


I first converted the grams to moles and the pressure to atm. I attempted this problem by setting the first and after values to each other. I used PV/n = PV/n (before and after). When I set these equal to each other I get approx. 4.6 mol He or approx. 9 grams He. Is this a legal way to approach this problem?
 
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brake4country said:
legal way
Conditionally. The notation is not what it could be. Subscripts, insertion of masses in the appropriate places would improve things.
brake4country said:
PV/n = PV/n (before and after)
It's not obvious that you've done anything without some remarks about initial and final "states" and values.
brake4country said:
approx. 9 grams He
Don't overuse the word "approximate" or its derivatives or abbreviations when you've got an exact answer based on the problem statement.
 
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