Marterial Science (Chemistry Related) Problem

  • Thread starter Thread starter Double A
  • Start date Start date
  • Tags Tags
    Science
AI Thread Summary
In a MOS device, the problem involves calculating the number of silicon (Si) and oxygen (O) atoms in a 100 nm thick SiO2 layer with a density of 2.20 Mg/m^3. The solution begins by determining the mass of the oxide layer per square millimeter using the given density and thickness. From the mass, the number of Si and O atoms can be calculated using their atomic weights. One participant successfully calculated 2.21x10^15 Si atoms and 4.41x10^15 O atoms but sought clarification on the formulas used. The discussion emphasizes the importance of correctly applying density and atomic weight to derive the atom counts.
Double A
Messages
30
Reaction score
0
Material Science (Chemistry Related) Problem

I am having a hard time starting my solution to the following problem:

In a metal-oxide-semiconductor (MOS) device, a thin layer of SiO_2 (density = 2.20 Mg/m^3) is grown on a single crystal chip of silicon. How many Si atoms and how many O atoms are present per square millimeter of the oxide layer? Assume that the layer thickness is 100 nm.

So far I have been looking throughout the textbook at some sample problems but the sample problems are not asking for a similar solution to this question. I have also referred to my lecture notes and have not gotten any where for quite some time. Mentally I thought that I could find the volume of the silicon oxide but I was incorrect in my mental calculations. Please help me get started.
 
Last edited:
Physics news on Phys.org
From the density and thickness, you can get the mass in a square millimeter of oxide. From there, you can get the number of Si and O atoms by knowing how much these atoms weigh.

Carl
 
Thanks I did arrive at a solution of 2.21x10^{15} atoms of SI and 4.41x10^{15} atoms of O.
 
But What formula did you use? I did not get the same answers
 
yes, some clarification to this post is needed. what steps do u take to get those answers?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top