Mass balance for diffusion and analogy to heat conduction

[gfd43tg]

Hello,
I just began learning mass transfer, and I am trying to use analogies from heat transfer to help me solve problems. For example, if you have one dimensional heat transfer through a plane wall, I would start with a general energy balance.

$$\frac {dE}{dt} = \dot Q_{x} - \dot Q_{x + \Delta x} + \dot e_{gen}A \Delta x$$
$$ \rho A \Delta x \hat c_{p} \frac {dT}{dt} = \dot Q_{x} - \dot Q_{x + \Delta x} + \dot e_{gen}A \Delta x$$
dividing through and taking the limit as x approaches 0,
$$\rho \hat c_{p} \frac {dT}{dt} = - \frac {1}{A} \frac {d \dot Q}{dx} + \dot e_{gen}$$

Then using Fourier's law $\dot Q = -kA \frac {dT}{dx}$ I substitute and get
$$ \rho \hat c_{p} \frac {dT}{dt} = \frac {d}{dx} (k \frac {dT}{dx}) + \dot e_{gen}$$

Now I want to extend this to mass transfer, and I find my textbook to be sorely lacking in even properly showing a derivation from the beginning, so I try myself
$$ \frac {dm}{dt} = \dot m_{x} - \dot m_{x + \Delta x} + \dot m_{gen} A \Delta x$$
$$ A \Delta x \frac {d \rho}{dt} = \dot m_{x} - \dot m_{x + \Delta x} + \dot m_{gen} A \Delta x$$
Diving through and the limit as delta x approaches 0
$$ \frac {d \rho}{dt} = - \frac {1}{A} \frac {d}{dx} (-D_{AB}A \frac {d \rho}{dx}) + \dot m_{gen} $$
Now I can remove the generation term to get
$$ \frac {d \rho}{dt} = \frac {d}{dx} (D_{AB} \frac {d \rho}{dx})$$
Assume steady state, so then I integrate once
$$ D_{AB} \frac {d \rho}{dx} = C_{1} $$
$$ D_{AB} \rho = C_{1}x + C_{2} $$
Now what boundary conditions are appropriate to use?

 

[Chestermiller]

ρ=ρ(0) at x = 0
ρ=ρ(L) at x = L