1. The problem statement, all variables and given/known data A mass of 200 kg is hanging directly in the center of a chain; the chain makes a 20o angle from its horizontal. The chain will break if more than 2000 N of force are applied at any point on the chain. Will the chain break? 2. Relevant equations F=ma Tfy=mg(sin[itex]\Theta[/itex]) g=10m/s 3. The attempt at a solution 2000N = 2Tf(sin20) Tf1 = 1000/sin20 Tf1 = 1095 N Tf2 = 1095 N Tftotal = 1095N + 1095N Tftotal = 2190 N The chain will break.