(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A mass of 200 kg is hanging directly in the center of a chain; the chain makes a 20^{o}angle from its horizontal. The chain will break if more than 2000 N of force are applied at any point on the chain. Will the chain break?

2. Relevant equations

F=ma

Tfy=mg(sin[itex]\Theta[/itex])

g=10m/s

3. The attempt at a solution

2000N = 2Tf(sin20)

Tf1 = 1000/sin20

Tf1 = 1095 N

Tf2 = 1095 N

Tftotal = 1095N + 1095N

Tftotal = 2190 N

The chain will break.

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# Homework Help: Mass Hanging in Center of Chain Problem

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