Mass of a weight attached to a body

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The discussion revolves around a physics problem involving a wooden body with a mass of 4 kg and a coefficient of friction of 0.2, where the goal is to determine the mass of an attached weight that initiates movement. Participants clarify that the problem likely involves static friction and that the wooden body is in static equilibrium just before it begins to move. One contributor successfully solves the problem by setting the acceleration to zero and using force equations to find the mass of the weight. The importance of correctly interpreting the problem statement and the role of static friction in determining the mass required for movement is emphasized. The conversation highlights the need for clear communication in problem-solving scenarios.
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Homework Statement


A weight is attached to a wooden body with mass M=4kg lying on a horizontal surface. The coefficient of friction is μ=0.2. What is the mass m of the weight so that the wooden body is moving?

Image:
gwjxVCd.png


Homework Equations


Equations of forces

The Attempt at a Solution


I tried drawing all the forces that apply on both bodies and then make an inequality where the total sum of the forces applying on the weight is bigger than the ones on the wooden body, but I get an unknown value for the acceleration. Help would be appreciated.
 
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Hi AndrejN96. Welcome to Physics Forums.

The problem statement isn't clear. Is this the exact wording? If not, please provide the exact wording.

Chet
 
AndrejN96 said:
I tried drawing all the forces that apply on both bodies and then make an inequality where the total sum of the forces applying on the weight is bigger than the ones on the wooden body, but I get an unknown value for the acceleration. Help would be appreciated.
The approach looks good. To see what went wrong, please show your full work here.
 
Chestermiller said:
Hi AndrejN96. Welcome to Physics Forums.

The problem statement isn't clear. Is this the exact wording? If not, please provide the exact wording.

Chet
Hi, yes this is the exact wording, as taken from a college exam, just translated to English.
mfb said:
The approach looks good. To see what went wrong, please show your full work here.
This is what I'm currently at: http://i.imgur.com/TDftcan.png

I've gathered the sums of the forces by x and y-axis of the two objects as presented to us in class and now I am unsure how to continue.
 
I'm going to make some guesses about this problem statement, which has probably lost some things in the translation.

1. The coefficient of friction that is given is the coefficient of static friction
2. The question should read: What is the mass m of the weight so that the wooden body just begins to move?

So I think we are dealing with a static friction problem here, and the system is in static equilibrium, but on the verge of moving.

Chet
 
Chestermiller said:
I'm going to make some guesses about this problem statement, which has probably lost some things in the translation.

1. The coefficient of friction that is given is the coefficient of static friction
2. The question should read: What is the mass m of the weight so that the wooden body just begins to move?

So I think we are dealing with a static friction problem here, and the system is in static equilibrium, but on the verge of moving.

Chet
You're probably correct. I am unsure as what the terminology is in English as translating it literally from my language just makes no sense. I did manage to solve it myself though, solving for acceleration and then finding values for m so that a>0.
 
The problem asks us to find the 'm' at which wooden block begins to move. In such types of problem the acceleration of the system tends to be zero.
So you equations should be
##f_{t}=T##
and ##T=mg##
Can you find ##m## from here?
 
Satvik Pandey said:
The problem asks us to find the 'm' at which wooden block begins to move. In such types of problem the acceleration of the system tends to be zero.
So you equations should be
##f_{t}=T##
and ##T=mg##
Can you find ##m## from here?
Oh, so the acceleration should be zero at that point?
 
Just before the block begins to slide (but is still not moving), the acceleration is zero, yes.
 

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