Max Mass Dresser Liftable w/ 150N Force - 46kg

  • Thread starter Thread starter gmichel395
  • Start date Start date
  • Tags Tags
    Mass
AI Thread Summary
The discussion revolves around calculating the maximum mass of a dresser that can be lifted using a pulley system with a force of 150N. Participants analyze the number of rope sections supporting the load, initially miscounting but ultimately agreeing on six sections. Using the formula for tension, they conclude that the effective lifting force is 900N (6 sections x 150N). Dividing this by the acceleration due to gravity results in a maximum mass of approximately 92kg. The final consensus is that the closest answer to the maximum mass of the dresser is 92kg.
gmichel395
Messages
10
Reaction score
0

Homework Statement


"Using the pulley system shown to lift the heavy dresser, the person is applying a force of 150N to the end of the rope. Which of the following is closest to the maximum mass of the dresser that can be lifted with this force? [Ignore weight & friction from pulleys/rope.]"

A) 46kg
B) 92kg
C) 110kg
D) 150kg
E) 180kg

20160401_203844~2[1].jpg
2. Homework Equations

Newton's 2nd & 3rd laws

The Attempt at a Solution


So she's pulling with 150 N and there are three pulleys connected to the dresser, so her effort is tripled. 450N lifts the dresser and so the mass is 46kg?
 
Physics news on Phys.org
Label each section of the rope with its tension. How many sections of rope are supporting the dresser?
 
I count six sections plus the one the girl is holding so seven. 7*150 divided by g gives approximately 110kg?
 
gmichel395 said:
I count six sections plus the one the girl is holding so seven. 7*150 divided by g gives approximately 110kg?
The one the girl is holding is holding the girl...not the dresser. So one less. You want to count only the ropes that are directly supporting the load.
 
Ah so six. And the answer is 92kg?
 
gmichel395 said:
Ah so six. And the answer is 92kg?
Yes.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top