Solving the Force Monkey Problem: Bush Baby Physics

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In summary, the bush baby jumps 2.3 meters high and accelerates over a distance of 0.16 meters at a constant speed. It exerts a force of 500 newtons on the ground while jumping.
  • #1
Ivawen
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Homework Statement



A bush baby a small african primate with a mass of 200 grams is capable of leaping vertically to the remarkable height of 2.3m. To jump this high the bush baby accelerates over a distance of 0.16m while rapidly extending its legs . The accelertion during the time the bush baby is pushing off is approximately constant . How much force does the bush baby exert on the ground while it is pushing off ?

Homework Equations


KE max = GPE max
1/2m^2=Max Gpe
impulse = Favrg*t

The Attempt at a Solution


well i know that this problem can be solved by using the potential energy and kinetic energy. But our professor assigned this problem while we did not get to this yet. So is there another way to solve this problem let say by using 1st 2nd or 3rd Newtons forces laws and kinematics ?
 
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  • #2
It's possible yes. Which part of the question did you use energy for? If it's the height you otherwise know that the maximum height is when the velocity is 0. So you get an equation ##v_0-gt = 0##. After you have ##v_0##(the velocity after acceleration ends) you could calculate the initial acceleration and then the force.

Edit: I assume this is calculas bases physics, the chain rule comes in handy.
 
  • #3
Have you studied the equations of motion? (eg SUVAT).
 
  • #4
Incand said:
It's possible yes. Which part of the question did you use energy for? If it's the height you otherwise know that the maximum height is when the velocity is 0. So you get an equation ##v_0-gt = 0##. After you have ##v_0##(the velocity after acceleration ends) you could calculate the initial acceleration and then the force.

Well the baby obtains the jump by using MAX GPE = mgh
then set KE max = Gpe max to get intial speed as it leaves the ground
but i kind get my head twisted when trying to solve it using motion law well tnx for your reply
 
  • #5
CWatters said:
Have you studied the equations of motion? (eg SUVAT).
yes we did
 
  • #6
Ok so divide the problem into two phases. The launch phase (0 to 0.16m) and the coasting phase (0.16m to 2.3m). Write down what you know about the coasting phase and calculate the required initial velocity.

Edit: Perhaps "coasting" phase is the wrong term. "Decelerating phase" might be better.
 

What is the Force Monkey Problem?

The Force Monkey Problem is a hypothetical physics problem that involves a monkey hanging from a branch and trying to reach a bush baby on another branch. The question is, what is the minimum amount of force the monkey needs to exert to reach the bush baby?

What makes solving the Force Monkey Problem challenging?

Solving the Force Monkey Problem requires a deep understanding of physics principles such as Newton's laws of motion and torque, as well as the ability to apply these principles to a complex scenario involving multiple moving objects.

How can the Force Monkey Problem be solved?

The Force Monkey Problem can be solved by breaking it down into smaller, solvable problems. This involves analyzing the forces acting on the monkey and the bush baby, calculating the torque needed for the monkey to reach the bush baby, and determining the minimum force required to achieve this torque.

What factors can affect the solution to the Force Monkey Problem?

The solution to the Force Monkey Problem can be affected by a variety of factors, such as the distance between the monkey and the bush baby, the mass and position of the objects, and the strength of the branch that the monkey is hanging from.

How can the Force Monkey Problem be applied in real-life situations?

The Force Monkey Problem can be applied in various real-life situations, such as understanding the forces involved in rock climbing or determining the minimum force needed for a person to reach a hanging object. It can also be used to teach physics concepts and problem-solving skills to students.

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