Mass pulling another, rotating, mass

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AI Thread Summary
The discussion focuses on calculating the acceleration of a mass m, the angular acceleration of a mass M, and the tension in a system where a cylinder rolls without friction. Key equations used include Shteiner's theorem for moment of inertia and the relationship between torque and angular acceleration. The participant derives the acceleration of mass m as a function of gravitational force and the system's moment of inertia. The calculations confirm that the assumption of rolling without slipping is valid. Overall, the solution appears correct and well-structured.
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Homework Statement


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The cylinder rolls without friction. what's m's acceleration, M's angular acceleration and the tension.

Homework Equations


Shteiner's theorem: ##I_c=I_{c.o.m.}+Mr^2##
Torque and angular acceleration: ##M=I\alpha##
Moment of inertia of a solid cylinder: ##I_{cen}=\frac{mr^2}{2}##

The Attempt at a Solution


I denote the center variables with c
Kinematics (or geometry? which discipline is suitable for this relation):
$$x_c=\omega r~~\rightarrow~~\dot x_c=\alpha r~~\rightarrow~~\alpha=\frac{\dot x_c}{r}$$
$$\left\{ \begin{array}{l} mg-T=m\dot x_A~~\rightarrow~~T=m(g-\dot x_A)=m(g-2\dot x_c) \\ 2r\cdot T=I_B\frac{\dot x_c}{r} \end{array} \right.$$
$$\rightarrow~\dot x_c=\frac{2r^2mg}{I_B+4mr^2}=\frac{2r^2mg}{I_c+Mr^2+4mr^2}=\frac{2r^2mg}{\frac{Mr^2}{2}+(M+4m)r^2}=\frac{4mg}{3M+8m}$$
 
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I assume you meant "rolls without slipping".
Your use of x for velocity instead of displacement is unusual, but quite OK.
Your working and answer look right to me.
 
Thank you very much Haruspex
 
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