- #1
Mozart
- 106
- 0
My final math exam is tomorrow, and I am having trouble with some questions as I go through this review package.
I have the answers so its very frustrating to arrive at the wrong answer over, and over.
Anyways the question is:
The position of a bucket on a circular tar sands excavator is given by the equation: p(t)= 10sin(6pit + 3pi) + 20
Where t is the time in minutes. There are 20 buckets on the excavator and each holds 500 kg
How many kilograms of tar sands are excavated in one hour?
The answer is 1800000 kg
This is what I did: p(t)=10sin(6pi(60)+3pi) + 20
P(t)= 28.69
from here I am lost so I just did 500 x 20= 10000
10000 x 28.69= 286900 kg
Can someone please help me? Thanks
I have the answers so its very frustrating to arrive at the wrong answer over, and over.
Anyways the question is:
The position of a bucket on a circular tar sands excavator is given by the equation: p(t)= 10sin(6pit + 3pi) + 20
Where t is the time in minutes. There are 20 buckets on the excavator and each holds 500 kg
How many kilograms of tar sands are excavated in one hour?
The answer is 1800000 kg
This is what I did: p(t)=10sin(6pi(60)+3pi) + 20
P(t)= 28.69
from here I am lost so I just did 500 x 20= 10000
10000 x 28.69= 286900 kg
Can someone please help me? Thanks