mtayab1994
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yea and for x<0:
f(0)=f(k^{2}+f(f(-k^{2})) which then equals
=f(-k^{2})-k^{2}
f(0)=f(k^{2}+f(f(-k^{2})) which then equals
=f(-k^{2})-k^{2}
mtayab1994 said:yea and for x<0:
f(0)=f(k^{2}f(f(-k^{2})) which then equals
micromass said:Typo here??
yea i fixed it before you posted and btw the proof is as follows:
f(x)=-x+cfor c+f(0)<br /> <br /> indeed: f(x^{2}+f(y))=x^{2}-f(y)+c<br /> <br /> as: f(y)=-y+c then f(x^{2}+f(y))=-x^{2}+y-c+c<br /> <br /> and finally f(x^{2}+f(y))=y-x^{2} for every x in ℝ