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Math Problem/ Mental Lapse

  1. Jan 7, 2005 #1
    Hi

    I am having a little bit of a mental lapse right now :cry: :zzz: :yuck: and I was wondering if someone could help me out.

    I want to write the formula as

    3(cos^2(x)sin^2(x)) to the identity sin2x = 2sinxcosx

    Thanks ALOT!!!!!!!
     
    Last edited: Jan 7, 2005
  2. jcsd
  3. Jan 7, 2005 #2

    arildno

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    Note that:
    [tex]\cos^{2}x\sin^{2}x=(\cos{x}\sin{x})^{2}=(\frac{2\cos{x}\sin{x}}{2})^{2}[/tex]
     
  4. Jan 7, 2005 #3
    Thanks arildno....
     
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