Matrices and eigenvalues. A comment in my answer.

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SUMMARY

The discussion centers on the properties of matrices and their eigenvalues, specifically addressing the question of whether there are infinite matrices with the same eigenvalues of 3 and 7. The participant correctly concludes that there are indeed infinite matrices with these eigenvalues, as demonstrated by the example matrix [3, a; 0, 7], where 'a' can be any real number. This confirms that the set of matrices sharing the same eigenvalues is not finite, as variations in eigenvectors lead to different matrices.

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Homework Statement



Hello and thanks again to anyone who has replied my posts. Your help is a great deal and really appreciated.

I have the following homework question which I have answered and I want a comment if it is valid or illogical:

We are given a matrix, with eigenvalues 3 and 7 respectively.

We are asked to say if there other matrices with the same eigenvalues and if the set containing all these matrices is finite.



Homework Equations


the matrix given:

2 1
-5 8

The Attempt at a Solution



I have thought of the following answer: My point is that there are infinite matrix with the same eigenvalues that have different eigenvectors. So I say that the linear system:

A(x1,y1)=λ1(x1,y1)
A(x2,y2)=λ2(x2,y2)

where A is a 2x2, has infinite solutions IF we take a11,a12,a21,a22(the elements of the matrix) as the variables of the linear system. The solutions will have x1,y1 and x2,y2 as constant parameters.

Have i got something terribly wrong?
 
Last edited:
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No, that's perfectly correct.

Another way to prove that is to note that the matrix
\begin{bmatrix}3 & a \\ 0 & 7\end{bmatrix}
has eigenvalues 3 and 7 for any a.
 

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