Matrix representation of certain Operator

abcs22
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Homework Statement


Vectors I1> and I2> create the orthonormal basis. Operator O is:
O=a(I1><1I-I2><2I+iI1><2I-iI2><1I), where a is a real number.
Find the matrix representation of the operator in the basis I1>,I2>. Find eigenvalues and eigenvectors of the operator. Check if the eigenvectors are orthonormal. [/B]

Homework Equations



Av=λv

The Attempt at a Solution



My problem is concerning the first part of this excercise. I'm not really familiar with this notation of the operator and not sure how I should get the matrix. I have tried improvisation and got the matrix

2a^2 -2a^2
-2a^2 2a^2

When I tried to calculate eigenvalues, I didn't get anything reasonable, so I believe that my matrix is wrong. Please help me regarding this problem, once I have the right matrix I will not have the problem finding eigenvalues nor eigenvectors.
 
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Hint: The matrix element ##O_{ij}## of an operator ##O## is given by ##\langle i|O|j\rangle##.
abcs22 said:
I'm not really familiar with this notation of the operator
That is actually the vector form of the relation for a matrix ##M##
$$
M = \sum_i\sum_j M_{ij} c_i r_j
$$
where ##c_i## is a column matrix containing 1 as the i-th element and zero otherwise and ##r_j## is a row matrix containing 1 as the j-th element and zero otherwise.
 
Thank you very much for your reply. I know the formula for the matrix element but have problem working it out with this notation. I was trying to find examples which include this notation, but without any luck.
 
abcs22 said:
have problem working it out with this notation
What's the problem, for example ##\langle 1 |O| 2 \rangle = i a\langle 1| 1 \rangle \langle 2 |2 \rangle = ia##.
 
Last edited:
I don't understand how you got i<1l1><2l2> and also, what to do with that scalar a in front of the bracket
 
abcs22 said:
I don't understand how you got i<1l1><2l2>
From ##\langle 1 |O| 2 \rangle##, replace ##O## with the form you are given with in the first post and then make use of the fact that ##|1\rangle## and ##|2\rangle## are orthonormal.
abcs22 said:
what to do with that scalar a in front of the bracket
Sorry I forgot to add ##a##. Corrected.
 
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