Matrix Similarity and Eigenvalues

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Homework Statement


If two 3 x 3 matrices A and B have the eigenvalues 1, 2, and 3, then A must be similar to B. True or False and why.

Homework Equations


A is similar to B iff B = S^-1AS

The Attempt at a Solution


I know that if A and B are similar then they have the same eigenvalues but the same does not always hold true the other way. For example, [1 0 ## 0 1] and [1 1 ## 0 1] both have eigenvalues of 1 and 1 but the first is diagonalizable and the second is not so they are not similar. However, I cannot find a counterexample for a 3 x 3 matrix. Any thoughts? Thank you!
 
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Think about why you can't diagonalize the matrix

\begin{pmatrix}1 & 1 \\ 0 & 1\end{pmatrix}

What problem do you run into when you try to diagonalize it? Will that same problem crop up with A and B?
 
Since the eigenvalues are given and they are 3 unique eigenvalues then there will be an eigenbasis and the matrices will both have to be diagonalizable therefore, the statement is true (am I on the right track?).
 
Yup, you got it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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