Max Acceleration for 10kg Package: Physics Homework Solution

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The maximum acceleration for a 10kg package being pulled by a rope that can withstand 1000N of tension is calculated using Newton's second law, F=ma. Given that the tension in the rope is the force causing the acceleration, the maximum acceleration is 100 m/s². If the acceleration exceeds this value, the tension would surpass 1000N, leading to the rope breaking. Therefore, the solution confirms that 100 m/s² is the greatest acceleration that will not break the rope. Understanding the relationship between force, mass, and acceleration is crucial in solving this physics problem.
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Homework Statement



a rope can withstand 1000kg N of tension. if the rope is being used to pull a 10kg package across a frictionless surface, what is the greatest acceleration that will not break the rope?

Homework Equations





The Attempt at a Solution



Not even sure.

is it 100m/s2
 
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The units of tension are N, not kg*N. And yes, a=100m/s^2. You used F=ma, right?
 
yes

so that is the maximum amount of accerlation?
 
Yes, the tension in the rope is the force causing the acceleration. If the acceleration were larger, then the tension in the rope would be > 1000N. It would break.
 

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