Max Acceleration for Truck w/Crate & CoFriction

AI Thread Summary
To determine the maximum acceleration of a 5228 kg flatbed truck with a 226 kg crate, the static coefficient of friction of 0.27 must be applied. The gravitational force acting on both the truck and the crate is calculated, but the focus should be on the horizontal forces. The maximum frictional force, which prevents the crate from slipping, is found by multiplying the normal force (weight of the crate) by the coefficient of friction. Understanding that acceleration is horizontal is crucial for applying the correct forces in the calculations. The discussion emphasizes the importance of recognizing the relationship between friction and applied forces in solving the problem.
rmalski
Messages
13
Reaction score
0

Homework Statement

[/B]A 5228 kg flatbed truck has a 226 kg crate resting on the level bed. If the static coefficient of friction is 0.27, what is the maximum acceleration the truck can achieve without the crate slipping off?

Homework Equations

[/B]f=ma

The Attempt at a Solution


i believe i need to find the force on each object. it would be 5228 x 9.8 and 226 x 9.8 but i am stuck there, especially with the static coefficient of friction. i do not understand that at all
 
Physics news on Phys.org
The forces you mention are from gravity. Works in a vertical direction. But we can assume there is no vertical acceleration. So there must be more forces at work.
Acceleration is probably in a different direction (I don't spoil the exercise if I say: horizontal). How do you bring in a force that works in a horizontal direction ?
 
to find the horizontal force would you have to multiply the mass by the coefficient of friction?
 
Coëfficiënt of friction is dimensionless: it is the ratio of (the magnitude of) two forces. Which ones ?
 
the friction force and applied force?
 
No.

Physics isn't a guessing game. What have you learned about this subject ?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Static friction coefficient for a crate in the back of a truck
Replies
6
Views
2K
What Is the Minimum Stopping Distance to Prevent Crate Sliding?
Replies
3
Views
4K
Truck carrying a box, friction problem
Replies
10
Views
5K
How many crates can you load in a minute with different average power outputs?
Replies
1
Views
2K
What Forces Keep the Crate Stationary in an Accelerating Truck?
Replies
1
Views
2K
Maximum Acceleration of sliding crates
Replies
6
Views
2K
Maximum Acceleration for Crate on Moving Flatbed
Replies
2
Views
2K
How Can the Acceleration of a Crate on a Truck Be Determined?
Replies
11
Views
2K
How Does Sliding Affect the Force Exerted by the Road on a Truck?
Replies
4
Views
1K
A flatbed truck and Static Friction and Crate breaking loose
Replies
8
Views
4K

Hot Threads

Recent Insights

Back
Top