Max Compression of Spring with Friction: Solve Now!

AI Thread Summary
The problem involves a 1 kg puck sliding at 20 m/s that compresses a spring with a constant of 35 N/m while experiencing a frictional force of 4.0 N. To find the maximum compression of the spring, the initial kinetic energy of the puck is equated to the energy stored in the spring and the work done against friction. The equation used is 0.5mv^2 = 0.5kd^2 + Fd, leading to a quadratic equation. The calculated maximum compression of the spring is approximately 3.3 meters. This solution effectively incorporates the effects of friction on the system's energy balance.
kerrwilk
Messages
14
Reaction score
0
A 1 kg puck slides at 20m/s along ice, then hits and compresses a spring with a constant of 35N/M. When it first hits the spring, the puck experiences a frictional force of 4.0 N opposing its motion. What is the maximum compression of the spring?



Homework Equations

KE=1/2mv^2



The Attempt at a Solution

I can do these problems without the friction element but am unsure about how friction affects the outcome. Any help would be appreciated.
 
Physics news on Phys.org
Initial KE = energy of spring + work done against friction
 
Thanks for your help Delphi51. Is this how I would solve the problem?

.5mv*2=.5kd*2+Fd
.5(1)(20)*2=.5(35)d*2+(4)d
200=17.5d*2+4d
0=17.5d*2+4d- 200
d= 3.3m (quadratic formula)

Thanks again.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

How to find the max. compression of a spring given a block on an incline?
Replies
17
Views
6K
A block of mass m is dropped onto the top of a vertical spring....
Replies
8
Views
5K
Elastic potential energy (spring) problem
Replies
3
Views
2K
Max Spring Compression and Object Velocity on Frictionless Ramp
Replies
3
Views
2K
Solving for Max Compression: 0.2kg Spring
Replies
12
Views
1K
Mass sliding on frictionless inclined plane compresses a spring
Replies
7
Views
3K
The coefficient of friction by spring compression
Replies
1
Views
3K
Energy Problem with Spring, Gravity, and Friction
Replies
2
Views
1K
Firefighter sliding down pole onto spring
Replies
4
Views
4K
Time to Max Compression of a Spring
Replies
2
Views
2K

Hot Threads

Recent Insights

Back
Top