Max Compression of Spring with Friction: Solve Now!

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SUMMARY

The maximum compression of a spring when a 1 kg puck sliding at 20 m/s compresses it, while experiencing a frictional force of 4.0 N, is calculated to be 3.3 meters. The spring has a constant of 35 N/m. The solution involves equating the initial kinetic energy of the puck to the energy stored in the spring and the work done against friction, leading to the quadratic equation 0 = 17.5d² + 4d - 200.

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  • Understanding of kinetic energy (KE = 1/2 mv²)
  • Knowledge of spring constants (Hooke's Law)
  • Familiarity with quadratic equations
  • Basic principles of friction and work
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A 1 kg puck slides at 20m/s along ice, then hits and compresses a spring with a constant of 35N/M. When it first hits the spring, the puck experiences a frictional force of 4.0 N opposing its motion. What is the maximum compression of the spring?



Homework Equations

KE=1/2mv^2



The Attempt at a Solution

I can do these problems without the friction element but am unsure about how friction affects the outcome. Any help would be appreciated.
 
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Initial KE = energy of spring + work done against friction
 
Thanks for your help Delphi51. Is this how I would solve the problem?

.5mv*2=.5kd*2+Fd
.5(1)(20)*2=.5(35)d*2+(4)d
200=17.5d*2+4d
0=17.5d*2+4d- 200
d= 3.3m (quadratic formula)

Thanks again.
 

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