Max Height & Time In Air of Ball Thrown Upward from 25m

AI Thread Summary
A ball thrown straight up from a height of 25 meters at a speed of 11 m/s reaches a maximum height of approximately 31 meters. To determine how long the ball is in the air, first calculate the time taken to reach the maximum height using the equation v = u + at. The time to reach the original height of 25 meters is double the time taken to reach the maximum height. The total time in the air is the sum of the time to reach maximum height and the time to fall back to the ground. This approach effectively combines kinematic equations to solve the problem.
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A ball is thrown straigh up, from height of 25 m above the ground, at a speed of 11 m/s.
The first question is what is the max. height of the ball above the ground.
I got that one it's like 31m. But there was another question after that that asks how long is the ball in the air. What equation must I use to find this out?
 
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When does the ball 'stop' being in the air?
 
well first find the time taken to reach the max ht. double this time it is the time taken for the ball to reach the ht it was thrown from(25m ) at this pt the ball has a speed of 11m/s use s =ut+4.9t^2 to find this t2 add this to t1 and that is the time taken to reach the ground. to find time to reach max ht use v = u+at.
 

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