Max Hill Steepness for a Cyclist: Solving the Problem

  • Thread starter Thread starter ndwiseguy
  • Start date Start date
  • Tags Tags
    Hill Max
AI Thread Summary
To determine the maximum steepness of a hill a cyclist can climb, start by calculating the force exerted by the cyclist based on their weight and the efficiency of the bike. The cyclist can exert a force equal to 0.90 times their weight, while the bike's mass adds to the total weight. The gear ratios from the sprockets and the radii of the pedals and wheels will help in calculating the torque and ultimately the force the tires exert on the ground. Ignoring friction simplifies the problem, as bicycles are highly efficient machines. Understanding these principles will lead to solving the steepness problem effectively.
ndwiseguy
Messages
7
Reaction score
0
Ok now, i know it says that i should show the work I've done on the question. Problem is, I have no idea where to start. So here is the question:

Assume a cyclist of weight w can exert a force on the pedals equal to 0.90w on the average. If the pedals rotate in a circle of radius 18cm, the wheels have radius of 34cm, and the front and back sprockets on which the chain runs have 42 and 19 teeth, respectively, determine the maximum steepness of hill the cyclist can climb. Assume bike mass is 12kg and rider mass is 60 kg. Ignore friction.

If you could tell me where to start that would be great.
 
Physics news on Phys.org
What do you think you should do? What have you tried?

If you can figure out the force that the tire exerts on the ground, you're almost there.

You could cheat, and claim that w/o friction the bike can't make it up the hill. ;)
 
Last edited:
thank you very much
 
Bicycles are one of the most efficient machines known to humanity, so you can ignore friction as it amounts to be very little. A really good Bike can be ~95% to ~98% efficient (if I recall that one right) so the remaining 2% - 5 % is the friction part.

P.S. rarely will a back sprocket have an odd number of teeth (I've a friend with an eleven though) like 19, (cause it doesn't divide nicely into 360°) and the wheel radius are the wheel sizes in inches. A racing bike has 27 x 1 1/4 tires, so the wheel, when measured with a tape measure, will have a 27 inch diameter, 13.5 inch radius, and cheese, a "12 Kg" bike, WOW, heavy!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top