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Max Incline for Equipment

  1. Apr 3, 2015 #1
    Hey guys,

    Just want to make sure I'm doing everything right here with some simple calcs. My physics days are long gone and it's been a while since I looked at any of this stuff.

    A 10,000lb piece of equipment is placed on a flat surface. 2,000lbs horizontal pounds-force is required to move it (brakes on).

    Assuming the type of surface is the same, what slope/incline/decline does the equipment start sliding?

    The answer I have is quite simply;

    α = arcsin (2,000 / 10,000)
    α = 11.54 degrees

    Or, even simpler, since the coefficient of friction (more like sliding resistance) is 0.2, the slope is 20% which converts to 11.54 degrees.

    Please confirm that I have not yet gone senile. Thank you.
     
    Last edited: Apr 3, 2015
  2. jcsd
  3. Apr 3, 2015 #2

    mfb

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    I moved the thread to our homework section as this is very homework-like.

    If the 2000 N are independent of the incline, that is right.
    Usually, that force depends on the angle (but the coefficient of friction is constant).
     
  4. Apr 3, 2015 #3

    SammyS

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    No way for us to confirm that.

    I think that if you work this all out for an object on an incline with friction, μ = tan(θ). (It's only a slightly different result for your example.) There is a component of the weight parallel to the incline surface, when you tilt the incline.

    The details are a bit different for static vs. kinetic friction, but that's the general result.
     
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