Max speed of wave on a string from elastic limit given density

AI Thread Summary
To determine the maximum speed of transverse wave pulses in a steel wire without exceeding its elastic limit, the elastic limit (2.7 X 10^9 Pa) and the density of steel (7.86 X 10^3 kg/m^3) are essential. The relationship v = √(T/μ) can be utilized, where T is the tension and μ is the linear mass density. By recognizing that pressure equals force over area, the maximum tension can be expressed in terms of the elastic limit and the cross-sectional area. This allows for the speed to be rewritten in terms of pressure and density, facilitating the calculation. Understanding these relationships is crucial for setting up the problem correctly.
lizzyb
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How do I set this up? "The elastic limit of a piece of steel wire is 2.7 X 10^9 Pa. What is the maximum speed at which transverse wave pulses can propagate along this wire before this stress is exceeded? (The density of steel is 7.86 X 10^3 kg/m^3)

I know v = \sqrt{\frac{T}{\mu}} so I guess I'd solve for T? And how do I pull the force from the elastic limit without the area?

thanx!
 
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lizzyb said:
How do I set this up? "The elastic limit of a piece of steel wire is 2.7 X 10^9 Pa. What is the maximum speed at which transverse wave pulses can propagate along this wire before this stress is exceeded? (The density of steel is 7.86 X 10^3 kg/m^3)

I know v = \sqrt{\frac{T}{\mu}} so I guess I'd solve for T? And how do I pull the force from the elastic limit without the area?

thanx!
Hi.

Notice that \rho = { mass \over length \times area} and \mu = {mass \over length} so that \rho = {\mu \over area} where, by "area" I mean the cross sectional area.

Also, Pressure = Force over area, so P_{max} = {T_{max} \over area}. With this you should be able to rewrite the speed in terms of the pressure and the volume mass density \rho.

I hope this helps

Patrick
 
yes it helped! i hope i remember it! thanks!
 
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