Max Torque for Steel Torsion Bar - Calculate Now

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To calculate the maximum torque for a steel torsion bar with a diameter of 20mm and an allowable shear stress of 200 MPa, the relevant formula is τ = Tr / J, where τ is shear stress, T is torque, r is radius, and J is the second polar moment of area. The modulus of elasticity (E = 209 GPa) is not needed for this calculation, as the maximum torque depends solely on the material's shear stress and the bar's geometry. Instead, the shear modulus (G) would be required if calculating rotation. The discussion clarifies the importance of focusing on shear stress and geometry rather than elasticity in torque calculations. Understanding these principles is essential for accurate engineering assessments.
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A cylindrical torsion bar made of steel (E = 209 GPa) with diameter of 20mm. The allowable shear stress for this material is 200 MPa what is the max torque that can be safely applied to this bar.

\tau = Tr / J

\tau = shear stress
T = torque
r = radius
J= second polar moment of area

I was thinking of using this formula but I would not have used E = 209GPa in my solution is this wrong? If so could somebody point me in the right direction.
 
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You are correct, you don't need E; the max torque is a function of the max stress and the geometry of the section. It is not related to the elasticity modulus. You would need the shear modulus G if you wanted to calculate the amount of rotation, not the stress.
 
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