Maximizing Seed Germination: Calculating Probability without Binomial Theorem

  • Thread starter Thread starter eldrick
  • Start date Start date
  • Tags Tags
    Probability
eldrick
Messages
52
Reaction score
0
A certain type of seed has a probability of 0.8 of germinating. In a pack of 100 seeds, what is the probability that at least 75% will germinate?




Solution can be achieved on a calculator using binomial theorem. Is there any other way of doing it without using binomial theorem ?
 
Physics news on Phys.org
You could use the normal distribution approximation, with "half- integer correction".

A binomial distribution in which the probability of a single success is p, repeated n times, has mean \mu= np and standard deviation \sigma= \sqrt{np(1-p)}. If n is large, the normal distribution with the same mean and standard deviation is a good approximation.

Since a normal distribution allows real number values while a binomial distribution requires integers, you interpret any real number that rounds to a particular integer as being that integer. Here, "at least 75%" or "at least 75 out of 100" would be equivalent to "74.5 or larger". That's the "half integer correction".
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top