Maximizing the height of a bullet in cylindrical coordinates

Qbit42
Messages
45
Reaction score
0

Homework Statement


A gun can fire shells in any direction with the same speed v0. Ignoring air resistance and using cylindrical polar coordinates with the gun at the origin and z measure vertically up, show that the gun can hit any object inside the surface

z = \frac{v_{0}^{2}}{2g} - \frac{g\rho^{2}}{2v_{0}^{2}}


Homework Equations



\phi is fixed so any derivative terms can be neglected, making Newtons equations:

F_{\rho} = m\frac{d^{2}\rho}{dt^{2}}

F_{z} = m\frac{d^{2}z}{dt^{2}}


The Attempt at a Solution



I know how I should tackle this problem, but I can't get started. I want to use Newton's laws to solve for z(t) and \rho(t). Differentiate z(t) to solve for max height at t_{final}. Then solve \rho(t_{final}) for t_{final}(\rho) and use that to find z(\rho).

I have no idea how to solve Newtons equations in this case, it seems like F_{z} = F_{g} and I have no idea what expression to use for F _{\rho}

Edit: I do not know why my subscripts are being interpreted as superscripts but I can't get it to stop.
 
Last edited:
Physics news on Phys.org
Without getting into too much detail, the subscript/superscript thing is because of a feature of the browser layout. Don't mix LaTeX code with regular letters; it's better to put the entire equation or expression in LaTeX.

F_\rho = m\frac{\mathrm{d}^2\rho}{\mathrm{d}t^2}

and z(t) etc.

Anyway: you've correctly identified that the force in the z (vertical) direction is the force of gravity. What is the net force acting in the ρ (horizontal) direction? This part of the problem is simple projectile motion, except that the coordinates are labeled ρ and z instead of x and y as you might be used to.

Once you've found the functions z(t) and \rho(t), you will need to combine them to find z(\rho), and then differentiate - but not to find the max height. You should instead be looking at the direct 3D distance between the projectile and the launch point.
 
Thanks for the clarification on the superscript problem. I honestly have no idea what force would be acting on the bullet in the horizontal direction, its been a long time since I've done any classical mechanics and I always hated it (still do).

As to the differentiation part, If I have z(\rho) then I guess I'd want to differentiate with respect to \rho or \phi to maximize 3D distance.

Edit: Do I have to split the initial velocity into components based on angle between \rho and z? Like V_{oz} = V_{0}Sin(\theta) and V_{o\rho} = V_{0}Cos(\theta). Although I don't see how that would help since I need an expression for the time derivative of V_{0} and those are just constants.
 
Last edited:
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top