(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Given a coaxial cable with outer conductor of radiusb, and inner conductor of radiusa. Prove that maximum potential is obtained when a = b /e,eis base of natural log.

2. Relevant equations

gauss law, ...

3. The attempt at a solution

By using Gauss Law,

fora<r<b,

i have E = 2*k*[tex]\lambda[/tex] /r, where [tex]\lambda[/tex] = Q/L

then the potential difference, V= [tex]\int[/tex] E dr

V = 2*k*[tex]\lambda[/tex] ln (b/a),

but i am not sure how to continue by differentiating V wrta.

Help me pls...

Thank you.

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# Maximum potential (coaxial cable)

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