- #1
grusini
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The maximum power that a train [tex]A[/tex] of mass [tex]m[/tex] can exert when traveling at a velocity [tex]v[/tex] is [tex]Pv^{3/2}[/tex] where [tex]P[/tex] is a constant. The resistance to motion is [tex]kv[/tex].
Why is the equation of motion of [tex]A[/tex] at full power given by: [tex]Pv^{1/2}-kv=m\frac{dv}{dt}[/tex]?
Why is the equation of motion of [tex]A[/tex] at full power given by: [tex]Pv^{1/2}-kv=m\frac{dv}{dt}[/tex]?