Maximum power theory in electronics

AI Thread Summary
The discussion focuses on the maximum power theory in electronics, specifically how to determine when power is maximized in a circuit with internal resistance and load resistance. The key equation presented is W = E²R/(r+R)², where W represents power. The concept of setting the derivative dW/dR to zero is explained as a calculus method for finding maximum or minimum values of a function. An alternative approach suggested is to graph the function to visually identify the maximum point. The conversation emphasizes the importance of understanding calculus in analyzing power maximization in electrical circuits.
logearav
Messages
329
Reaction score
0

Homework Statement



Please see my attachment. From the circuit
Energy transferred to the load E = Ir + IR, where r is the internal resistance and R is Load Resistance. so
I = E/(r+R)

Homework Equations





The Attempt at a Solution


The Power W is W = I2R = E2R/(r+R)2
Upto this i understand. I can't understand the following steps
As R changes, so does W. W will be maximum when dW/dR is zero
that is d/dR(E2R/(r+R)2) = 0
My question is why W is maximum when dW/dR = 0. Why dW/dR concept is introduced here
 

Attachments

  • 97fin-fig1a.gif
    97fin-fig1a.gif
    986 bytes · Views: 432
Last edited by a moderator:
Physics news on Phys.org
It's the basic calculus method for minimizing or maximizing a function. Take the derivative of the function with respect to the variable you wish to minimize (or maximize) with respect to, set the derivative equal to zero and solve for that variable. The resulting value(s) of the variable will either minimize or maximize the function.
 
Thanks gneill. But, can't this maximum theory be explained by any other concept other than calculus method. I can't understand this method.
 
logearav said:
Thanks gneill. But, can't this maximum theory be explained by any other concept other than calculus method. I can't understand this method.

Well, you could graph the function with respect to r and visually see the maximum :smile:
 
Thanks Gneill.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top