Maximum Power Transfer for Z = 12+24 Ohms

AI Thread Summary
To achieve maximum power transfer for a load impedance of Z = 12 + 24 ohms, the load impedance should be the complex conjugate, ZL = 12 - 24 ohms. The discussion emphasizes that the problem does not specify restrictions on varying the phase or magnitude of the load. Participants confirm that using the complex conjugate is the correct approach for this scenario. The conclusion is that ZL should equal the complex conjugate of the source impedance for optimal power transfer.
andytb1232000
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Homework Statement


Find the required value of the load to achieve maximum power transfer for Z = 12+24 ohms


Homework Equations



ZL = Zs

3. The Attempt at a Solution [/b

As the question does not state whether or not the phase or magnitude of the load can or cannot be varied. I believe the answer to be ZL= 12-24 ie the complex conjugate.
Does this seem correct?
 
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See http://www.allaboutcircuits.com/vol_1/chpt_10/12.html
 
andytb1232000 said:

Homework Statement


Find the required value of the load to achieve maximum power transfer for Z = 12+24 ohms


Homework Equations



ZL = Zs

3. The Attempt at a Solution [/b

As the question does not state whether or not the phase or magnitude of the load can or cannot be varied. I believe the answer to be ZL= 12-24 ie the complex conjugate.
Does this seem correct?


Yes.
 

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