Maximum Speed Formula for Simple Harmonic Motion

  • Thread starter Thread starter roughneck84
  • Start date Start date
  • Tags Tags
    Formulas Harmonics
AI Thread Summary
The discussion revolves around proving that the maximum speed (Vmax) of a mass on a spring in simple harmonic motion is given by the formula 2(pi)fA. A participant expresses difficulty in rearranging the relevant formulas and seeks assistance. Another contributor suggests using the energy equation Et = 1/2mv^2 + 1/2kx^2 to derive the relationship, emphasizing the importance of expressing total energy in terms of amplitude. The conversation hints at the use of calculus or trigonometric methods to simplify the proof. The exchange highlights the need for a solid understanding of the underlying physics concepts to solve the problem effectively.
roughneck84
Messages
13
Reaction score
0
I have been torturing myself with this problem for a couple weeks now and I am stumped. The unit I am working on is called simple harmonics. The question is:
Prove that the maximum speed (Vmax) of a mass on a spring is given by 2(pi)fA
I am guessing that the question wants me to re-arrange one of the formulas that was learned in this chapter but i am just lost.

Here are the formulas related to this unit.
Fx = -kx , W=1/2kx^2, T=[2(pi)r] / v , Et = 1/2mv^2 + 1/2kx^2, f = 1/2(pi) sq_rt(k/m)
or f = 1/2(pi) sq_rt a/-x

Please any help would be greatly appreciated
 
Physics news on Phys.org
OK. First off are you in a calculus based course? I ask because this can be proved in one to two lines with calculus.
 
somewhat. we learned trigonomic method. cosine law and pathagorean theorem
 
anyone ??
 
Do you know how to take a derivative?

If not, then try starting the problem this way:

Start with your energy equation:

Et = 1/2mv^2 + 1/2kx^2

First, try to get Et in terms of the wave's amplitude.

After this, fill in all the information for when v=v_max. Can you take it from here? If not, show me how far you can get.
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top