Maximum velocity of charged particles

AI Thread Summary
The discussion centers on calculating the maximum velocity of a charged particle in an evacuated chamber between two parallel metal plates connected to a power supply. For insulating plates, the particle experiences no electric field, resulting in zero velocity. In contrast, with conductive plates, the particle can gain kinetic energy, where the kinetic energy is expressed as KE = q*V = 1/2*m*v^2. The user seeks clarification on the application of the relevant equations and the effects of the chamber's construction on particle velocity. Understanding these principles is crucial for solving the problem effectively.
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Homework Statement



A particle, with a charge +q and a mass, m, is inserted into an evacuated chamber. The chamber is placed between two parallel metal plates that are a distance d apart, and are connectd to the terminals of a power supply that provide V volts (one plate to the positive terminal and one plate to the negative terminal.)

A. What is the maximum velocity that the field could give to the particle when the chamber is constructed so that the sides connecting the plates are insulating?

B. What is the maximum velocity that the field could give to the particle when the chamber is constructed so that the sides connecting the plates are good conductors?

Homework Equations



F=k*(q1*q2)/(d^2^)
[I'm not sure if this is what I need or not?]

The Attempt at a Solution



Would the velocity of the insulating plates be zero, since they don't allow charged particles to move through them?

I could use some help please. Thanks!
 
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Inside the box made up of metal, there will be no electric field. So the charged particle will not experience any force.
In the insulated box KE acquired by the charged particle is equal to q*V = 1/2*m*v^2
 
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