Maximum Volume of an Open Top Box

Carl_M
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Homework Statement


Is there another way to do this question?
Is this right?

L = 50-2x
W = 40-2x
Height= X

Homework Equations



//

V=L x W x H
V= (50-2x)(40-2x)(x)
V= (2000 -180x +4x²)(x)
V= 2000x -180x² +4x³
V= 4x³ - 180x² +2000x
V' = 12x² -360x +2000
X = (360 (+/-)sqrt(360²-4(12)(2000))) / 2(12)
X = 7.36...

How would I do this without using f ' ( x ) ? nor graph it

The Attempt at a Solution

 
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Are they asking you to do it without taking the derivative and setting it equal to zero?
Graphing is never necessary. Just for convenience.
 
No, but how would I do that?

It's not required or anything nor is it asked.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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