Maxwell-Boltzmann speed distribution derivatives

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SUMMARY

The discussion centers on the dynamics of molecules moving through a vacuum chamber and the conditions required for a molecule to reach a detector after passing through two rotating discs. The key equation derived is u = Lω/θ, where u represents the speed of the molecule, L is the distance between the discs (0.262m), ω is the common angular speed, and θ is the angular displacement. The participants clarify that the problem is straightforward and does not require complex velocity distribution analysis, focusing instead on the timing of the molecule's passage through the slits.

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devious b
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Hi everyone,

Molecules move into a vacuum chamber from an oven at constant T. The molecules then pass through a slit. They reach two rotating discs before finally reaching a detector.

Show that a molecule that passes through the first slit will reach the detector if it has speed, u = ωL/θ.

After it passes through the slit, the beam of particles is directed towards 2 discs that are a fixed distance apart (L). They both have a notch in them, the 2nd disc's notch is offset from the 1st by 1/6∏. T is constant, common angular speed is ω & L = 0.262m.

My question is, do I simply say that the most probable speed is equal to u?

√(2KT/m) = u = ωL/θ

Any clues would be appreciated.

Thanks:)
 
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I think you are looking too deep into the question. It's not about velocity distribution but they have given you a 'scenario' for a fairly straightforward dynamics problem. They just want to find which speed will get "a" molecule through the shutter which the two spinning slits present.
 
You're absolutely right, I completely over-thought the problem. So,

t1 = Time particle takes between the 2 discs = d/u = L/u

t2 = Time taken for disc 2 to reach correct position = θ/ω

For a particle to pass through both notches & hit detector, t1 must equal t2

So,

L/u = θ/ω → Lω/u = θ → u = Lω/θ

Thanks
 

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