How many ways can 25 pieces of varying shapes fit in a square space?

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To determine how many combinations of 25 pieces of varying shapes can fit into a square space, the specific quantities of each shape must be considered. The pieces include 7 medium squares, 3 large squares, 5 small squares, 2 long narrow rectangles, 4 medium rectangles, and 4 short narrow rectangles. The arrangement possibilities depend on the spatial constraints and the ability to place the shapes anywhere within the square. Calculating the combinations requires a clear understanding of the shapes' dimensions and how they interact within the given area. Ultimately, the solution hinges on the distribution and arrangement of these shapes within the defined space.
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I have a total of 25 pieces in 6 different shapes to fit in a given space. How many combinations can the pieces be put together to fit in the same given space?
 
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Homework Statement

I have 25 items total in 6 different shapes that all fit into a a given space. How many combinations can the 25 items fit into the same size space?

Homework Equations



Not sure

The Attempt at a Solution



Not sure
 
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You'd need to know how many of each of the 6 possible shapes there are, and if any of the shapes can go anywhere.
 
'Not sure' is right. I'm not even sure that's grammatical. Can you state that more clearly?
 
Yes, they can be placed anywhere within the space. (square shaped space) There are 7 medium sized squares, 3 large squares, 5 small squares, 2 long narrow rectangles, 4 medium rectangles and 4 short narrow rectangles.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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