me in the solution of this problem

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The problem involves determining the height above sea level where gravitational acceleration decreases by 1%. The formula for gravitational acceleration at 45 degrees latitude is given as g = a - bz, with a = 9.807 m/s² and b = 3.32 x 10^-6 s^-2. To find the height where weight decreases by 1%, the equation 0.99a = a - bx is used, leading to the solution x = 0.01a/b. The discussion highlights the importance of calculating the new value of g and clarifies the necessary steps to find the height. The conversation concludes with gratitude for the assistance provided in solving the problem.
shaiqbashir
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Hi!

Im getting confused in solving this problem. I just can't pick out the correct formulae to solve it.

"At 45 degree latitude, the gravitational acceleration as a function of elevation "z" above sea level is given by

g=a-bz

where a=9.807 meter per second square and b=3.32x10^-6 s^-2.

Determine the height above the sea level where the weight of an object will decrease by 1 percent."

Thanks in advance
 
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What is the value of "g",the one dropped by 1%...?And what is the height...?

Daniel.
 
My dear friend!

The height u r required to determine!
 
Well,that wasn't the question...:-p Did u computethe new "g"...?

Daniel.
 
Solution:
At z=0 (sea level); g=a
Say at height x the accelarion due to gravity is 99% i.e 0.99a. This is the height where the weight will be 99% too (F=mg).
So 0.99a=a - bx.

x = 0.01a/b.
 
It would have been much better,if the OP would have found the sollution...

Daniel.
 
Thanks a lot Snbose! You have helped me a lot

Thank u very much
 

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