- #1
madypa
- 1
- 0
Hello,
I have a 3d closed surface. This closed surface lies in a 3d vector field. I know the value of the vector at discrete points along the surface and the surface normal at these points. Essentially, say vector U and vector n at these points. This is the only information that I have. I need the *volume* mean of U in this closed surface. I also know that the divergence of U = 0. Seems trivial, but I can't seem to get through the calculation. Here is what I did:
mean(U) = 1/V ∫ U dV
where V is the volume enclosed by the closed surface.
Lets take the divergence on both sides, assuming mean U and U are continuously differentiable and the divergence and integration operators can be interchanged.
∇. mean(U) = 1/V ∫ ∇. U dV
= 1/V ∫_A U . n dA
So I can connect the divergence of mean of U with the information along the surface. However, I need the mean(U).
Any thoughts?
Thanks!
I have a 3d closed surface. This closed surface lies in a 3d vector field. I know the value of the vector at discrete points along the surface and the surface normal at these points. Essentially, say vector U and vector n at these points. This is the only information that I have. I need the *volume* mean of U in this closed surface. I also know that the divergence of U = 0. Seems trivial, but I can't seem to get through the calculation. Here is what I did:
mean(U) = 1/V ∫ U dV
where V is the volume enclosed by the closed surface.
Lets take the divergence on both sides, assuming mean U and U are continuously differentiable and the divergence and integration operators can be interchanged.
∇. mean(U) = 1/V ∫ ∇. U dV
= 1/V ∫_A U . n dA
So I can connect the divergence of mean of U with the information along the surface. However, I need the mean(U).
Any thoughts?
Thanks!