Mean Value Theorem problem help

Click For Summary

Homework Help Overview

The problem involves the Mean Value Theorem in the context of a function representing the number of units sold over time, specifically focusing on finding the average value of the function and determining when the derivative equals this average value.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the average value of the function over a specified interval and the implications of starting the time variable at different points, such as t = 0 versus t = 1.

Discussion Status

Some participants have attempted to clarify their understanding of the problem and the calculations involved, while others are questioning the assumptions regarding the starting point of the time variable. There is a mix of reinforcement and uncertainty about the correct approach.

Contextual Notes

There is an ongoing debate about the appropriateness of starting the time variable at t = 0 versus t = 1, with concerns about the implications of including or excluding the initial month in the calculations.

physicsman2
Messages
139
Reaction score
0

Homework Statement


A company introduces a new product for which the number of units sold S is
S(t)=200(5-(9/(2+t)) where t is the time in months

a) Find the average value of S(t) during the first year
b)During what month does S'(t) equal the average value during the first year


Homework Equations


f'(c)=(f(b)-f(a))/(b-a)


The Attempt at a Solution


well, i have no idea how to do it, but i believe for a), you have to find the derivative of the function(which i have no clue what it is) then use the equation given above to find the average value
For part b), i just have no clue
 
Physics news on Phys.org
i think i got it but i just need some reinforcement on my answers

for a), you do (f(12)-f(1))/(12-1) using the original equation since the interval for months is [1,12] since i don't think zero would be in that kind of interval
then for b) you would set that answer equal to the derivative of the equation and solve for t

am i right
 
Yes, although I suspect you start at t = 0.

For the derivative, I suggest working out the brackets and using the chain rule... do you know how to differentiate 1/u with respect to u?
 
Last edited:
i already found the derivative but why would you start at t = 0 if there really is no 0 month if the first month is 1
 
can someone please tell me why t = 0 and not 1
 
Sure, if you start at t = 1, then what about all that information from t = 0 to t = 1? (the first 30 days).
 
thanks it makes more sense
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K