Measuring resistance of thermistor in potential dividers

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Homework Help Overview

The discussion revolves around measuring the resistance of a thermistor using different circuit configurations, specifically comparing a simple circuit with an ohmmeter to a potential divider circuit. Participants are exploring the advantages of using a potential divider for this measurement.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the benefits of using a potential divider circuit over a simple resistance measurement setup. There are inquiries about the currents flowing through the thermistor in both circuits and how these currents impact the readings. Some participants are also discussing the relationship between electrical energy transformation and the thermistor's resistance.

Discussion Status

The discussion is ongoing, with participants providing insights and asking clarifying questions. Some guidance has been offered regarding the importance of understanding current flow and energy transformation in resistive circuits, but no consensus has been reached on the advantages of the potential divider circuit.

Contextual Notes

Participants are navigating concepts related to electrical measurements and the behavior of thermistors under different conditions. There is a mention of specific measurements taken, but the overall context remains exploratory without definitive conclusions.

lefty989
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Hi there, first off I hope this is ok to post here. Quite a simple question.
I have done an experiment simply to work out the resistance of a thermistor at different temperatures, I did a prelim with a simple circuit of just ohm meter + thermistor. Then I did the main one with a potential divider circuit.

1. What is the advantage of using a potential divider circuit over a simple one to measure resistance of a thermistor? (Read above)

Thanks for any replies. I'm a bit unsure as to why it would be better. :-/
 
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lefty989 said:
Hi there, first off I hope this is ok to post here. Quite a simple question.
I have done an experiment simply to work out the resistance of a thermistor at different temperatures, I did a prelim with a simple circuit of just ohm meter + thermistor. Then I did the main one with a potential divider circuit.

1. What is the advantage of using a potential divider circuit over a simple one to measure resistance of a thermistor? (Read above)

Thanks for any replies. I'm a bit unsure as to why it would be better. :-/

What were the currents flowing through the thermistor in two different circuits?
You can calculate this by getting a voltmeter and measuring the voltage output of your ohmmeter.

My voltmeter measures 3.051 vdc from my ohmmeter on the 2k ohm scale.
 
OmCheeto said:
What were the currents flowing through the thermistor in two different circuits?
You can calculate this by getting a voltmeter and measuring the voltage output of your ohmmeter.

My voltmeter measures 3.051 vdc from my ohmmeter on the 2k ohm scale.

Why is this necessary? I just need to know what makes this circuit a better way to do it.

But the current at say 20degrees was about 0.4 set at 20mA for potential divider. I didn't check the current for the other circuit. just had a resistance meter and thermistor.
 
lefty989 said:
Why is this necessary?
Because it points you to the answer.
I just need to know what makes this circuit a better way to do it.

But the current at say 20degrees was about 0.4 set at 20mA for potential divider. I didn't check the current for the other circuit. just had a resistance meter and thermistor.

You need to know how much current is flowing through the thermistor in each of the circuits, and how that current affects your readings. Are you familiar with the equations:
P = IE = I2R = V2/R

And how does P manifest itself in a purely resistive circuit?

And how does that affect R of the thermistor?

And how does that affect your measurements?

If you answer all of my questions, you will have the answer to your question.
 
Right... Thanks for the help..

Im not really understanding what you mean by the first question.
And how does P manifest itself in a purely resistive circuit?
Yes I do know the equations.
 
lefty989 said:
Right... Thanks for the help..

Im not really understanding what you mean by the first question.

OmCheeto said:
And how does P manifest itself in a purely resistive circuit?

(Excuse me for jumping in.)

I think OmCheeto is asking, what happens to the electrical energy when current flows through a resistor? (Hint: it gets transformed from electrical energy into ____ energy.)
 
Redbelly98 said:
(Excuse me for jumping in.)

I think OmCheeto is asking, what happens to the electrical energy when current flows through a resistor? (Hint: it gets transformed from electrical energy into ____ energy.)

Ahh ok. Hope I am right in saying heat energy? So a guess, does this mean the heat will affect the resistance output from the thermistor? That makes sense, so you use a potential divider circuit to eliminate that problem?
I am not quite sure why... (Is it something to do with the other resistor in series?)
 

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