Mechanical energy of a pendulum- I just can't get it

AI Thread Summary
The discussion focuses on calculating the mechanical energy of a pendulum with varying amplitudes. Initially, a pendulum with a length of 140 cm and an amplitude of 1.9 cm has a mechanical energy of 5.7 mJ. The user struggles to find the mechanical energy when the amplitude increases to 3.7 cm, initially arriving at an incorrect answer of 11.1 mJ. By applying the potential energy formula PE = 1/2 k x^2 and determining the spring constant k, the correct mechanical energy is calculated to be 21.62 mJ at the new amplitude. The conversation highlights the use of potential energy in simple harmonic motion for small amplitudes.
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Mechanical energy of a pendulum- I just can't get it!

Homework Statement



A pendulum of length 140 cm swings with an amplitude of 1.9 cm. Its mechanical energy is 5.7 mJ. What is the mechanical energy of the same pendulum when it swings with an amplitude of 3.7 cm?

Homework Equations



ME = PE + KE
PE = 1/2 k x^2
PE = mgh
KE = 1/2 m v^2

and I also know that at the top of the arc (amplitude) all of the energy is PE

The Attempt at a Solution



I keep trying to solve this and always end up with 11.1 mJ - this answer is wrong! I don't know what else to do.
 
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Why do you need to find the KE? Can you find the height difference between the extremities of the pendulum in the two cases?
 
I think we can just use the equation :

PE = 0.5kx^2

Where k is just a constant, so first we must find k from our initial data :

PE(2)/(x^2) = k
5.7(2)/(1.9^2) = k = 3.158

Now just use this value of k to solve the second part :

PE = 0.5(3.158)(3.7^2)
PE = 21.62 mJ

ME = PE at the max amplitude point, so ME = 21.62 mJ

I think that is right.
 
Thank you so much Retsam! That worked :D
I didn't know I could use PE = 1/2 k x^2 for pendulums; now I know!
Thank you!
 
For small amplitudes, you can use PE = kx^2/2. That means, you are essentially treating the simple pendulum as an SHM, in the regime where x is approximately equal to sin x. Geometrically, you would have got the same result, but this is the fastesr way.
 
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