Mechanical Energy: Solving for Work & Change in ME

AI Thread Summary
The discussion centers on calculating work done on a crate and understanding changes in mechanical energy. The first part of the homework involves using the formula for work, resulting in 6672 J when a constant force of 556 N is applied over 12 m. The second part questions the change in total mechanical energy, which is determined to be 0 J because the crate is not elevated or subjected to any forces that would change its energy state after being pushed. The conversation emphasizes that sliding the crate on a flat surface does not involve potential energy changes, as there are no forces acting to return it to a previous state. Ultimately, the understanding of mechanical energy in this context is clarified, confirming that no energy is gained or lost when the crate is simply moved horizontally without additional forces.
sweedeljoseph

Homework Statement


You use 556 N of constant force to push a crate 12 m horizontally across the floor, and then stop pushing, leaving the crate stopped in its new position:
a) How much work did you do on the crate?
b) What is the change in the total mechanical energy of the crate after being pushed (ingoring heat)?


Homework Equations


F(cos theta)d


The Attempt at a Solution


ANSWERS (from teacher):
a) 6672 J
b) 0 J

i know how to find the first question. you use the equation i gave. F is 556 N, cos theta is 1, and d is 12 m.

i don't understand how the second part is 0. am i supposed to use a certain formula? i know PE and KE but i don't have a mass in the problem. so what am i supposed to use to figure out what mechanical energy is?

if you could help me it would be great
i have a test on next tuesday
tryna study now instead of later

thank you!:-p
sweedeljoseph
 
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Think about what happens rather than just the formulae.
Work is force * distance for the first part.

For the second part, what has changed about the energy of the box?
Is there anythign you can do to get more energy out of the system in it's second state than in it's original state?
 
i have no idea. i just wrote the question how it was on my paper. there are no resources to use as a reference for the problem. that's just it. I am sure ill know how to solve it but I am not really sure what I am supposed to do. i know the answer is 0 that's it i don't know why.
 
Since work is force*distance, is there any force that is trying to return it to it's original position?

Imagine if you lifted the box up 1m, the force of gravity is trying to return it to it's original position so you can use this force to extract energy.
Similairly if there was a spring pulling it back you could use that.
 
would the mechanical energy be 0 because the crate isn't being lifted? its just being slid across the floor.

like when youre doing projectile motion? with the T chart of x and y values solving for v,vo,a,t,d the reason the y value of the vo will be 0 is because its staying in the air
something like that?
 
Yes pushing something along a level surface uses no energy except for friction.
 
thank you!
i understand it now
=]
 
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