Mechanics Question of a wheel chair

  • Thread starter Thread starter EIRE2003
  • Start date Start date
  • Tags Tags
    Mechanics Wheel
AI Thread Summary
To calculate the force required to keep a wheelchair moving up a 10-degree ramp at a constant speed, the gravitational force acting down the ramp must be considered. The total weight of the wheelchair is 900N, and the force can be determined using the formula F = mg sin(θ), where θ is the angle of the ramp. The power exerted by the person can be calculated by finding the work done against gravity over the distance of the ramp and dividing it by the time taken, which is 10 seconds. The inclined height of the ramp is approximately 0.87m, and the discussion emphasizes that friction is to be ignored. Understanding the balance of forces is crucial for maintaining constant speed while moving up the ramp.
EIRE2003
Messages
107
Reaction score
0
A person in a wheel chair is moving up a ramp at a constant speed. Their total weight is 900N. The ramp makes an angle of 10degrees to the horizon.
Calculate the force required to keep the wheel chair moving at constant speed up the ramp.
(You may ignore the effects of friction)

The ramp is 5m long. Calculate the power exerted by the person in the wheel chair if it takes her 10s to travel up the ramp.

Here is what i have done :confused:

- I used the SINE Rule to find the inclined height of the ramp, i found it to be .87m.

- Power = work/time.
 
Physics news on Phys.org
Start by finding the force needed to move the chair at constant speed up the ramp. Hint: Constant speed up the ramp means equilibrium. What are all the forces acting on the chair?
 
I still don't understand how to find the constant speed up the ramp??

All the forcesacting on the chair are gravity, friction (but friction is to be ignored). Is that it?
 
EIRE2003 said:
I still don't understand how to find the constant speed up the ramp??
If you want to find the speed you need distance and time. You are given both. (But you don't need to find the speed.)
All the forcesacting on the chair are gravity, friction (but friction is to be ignored). Is that it?
The forces acting on the chair are: gravity pulling down, the normal force of the ramp pushing on the chair, and the applied force pushing the chair up the ramp.

Consider the components acting parallel to the ramp: The applied force (F) pushing up the ramp, and the component of weight acting down the ramp (mg sinθ). These must balance for the chair to have constant speed.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top