What is the Linear Speed of a Child on a Rotating Merry-Go-Round?

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The discussion revolves around calculating the linear speed of a child on a merry-go-round that completes one revolution in 3.80 seconds, with the child seated 1.24 meters from the center. Key equations for linear velocity and angular velocity are referenced, emphasizing that tangential velocity is equivalent to linear velocity. Participants clarify the relationship between linear speed and centripetal acceleration, noting that circular motion involves centripetal acceleration. There is also a focus on study strategies and the importance of understanding the concepts rather than just memorizing equations. Overall, the conversation highlights the challenges of grasping physics concepts while preparing for exams.
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Homework Statement


A rotating merry-go-round makes one complete revolution in 3.80 s. What is the linear speed of a child seated 1.24 m from the center?


Homework Equations


vt = wr
w = 2(pi)/T
Vt = 2(pi)r/T


The Attempt at a Solution


I know that the further you are from the center, the higher velocity that you'll have, but I'm not sure where to go with that.
 
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kaylanp01 said:
A rotating merry-go-round makes one complete revolution in 3.80 s. What is the linear speed of a child seated 1.24 m from the center?

Hi kaylanp01! :smile:

hmm :rolleyes: … let's try an easy case …

how far does the child go in 3.80s? :wink:
 
You derived the equation, so just plug in your numbers.
 
LowlyPion said:
You derived the equation, so just plug in your numbers.

So that's the equation for linear velocity? I'm confused. I just grabbed that out of my notes.
 
tiny-tim said:
Hi kaylanp01! :smile:

hmm :rolleyes: … let's try an easy case …

how far does the child go in 3.80s? :wink:

Wellll...technically...he doesn't go anywhere, as he ends up in the same place ;).
 
kaylanp01 said:
So that's the equation for linear velocity? I'm confused. I just grabbed that out of my notes.

Well your notes were right.

The trick now is to understand what you took notes about then isn't it.
 
LowlyPion said:
Well your notes were right.

The trick now is to understand what you took notes about then isn't it.
I'm just trying to get through it now...try to pass the CAPA part of the course even if I can't pass the exam. haha. It says in my notes that the equation I derived above was for tangential v...so are tangential and linear the same thing?
 
kaylanp01 said:
I'm just trying to get through it now...try to pass the CAPA part of the course even if I can't pass the exam. haha. It says in my notes that the equation I derived above was for tangential v...so are tangential and linear the same thing?

Yes tangential V is linear V.
 
  • #10
LowlyPion said:
Yes tangential V is linear V.

Okay, great.
I looked at that website, and it eliminates my next question (I was going to ask how to calculate acceleration, but its all there) so you just saved me (and yourself) from more pain. haha.
Thank you (twice). :)
 
  • #11
LowlyPion said:
Yes tangential V is linear V.
Okay. I've been defeated. I still can't get acceleration.
I used a = 2.05/1.24 = 1.65 and that's not correct.
 
  • #12
The acceleration is the centripetal acceleration v2/r
 
  • #13
LowlyPion said:
The acceleration is the centripetal acceleration v2/r

So how will I know when its centripetal and when it isn't? I'm so confused. :(
 
  • #14
kaylanp01 said:
So how will I know when its centripetal and when it isn't? I'm so confused. :(

If it is undergoing circular motion its mass is undergoing centripetal acceleration.

When the disk is changing ω at some rate of increase that is called α, and it is called angular acceleration.
 
  • #15
LowlyPion said:
If it is undergoing circular motion its mass is undergoing centripetal acceleration.

When the disk is changing ω at some rate of increase that is called α, and it is called angular acceleration.


Okay, its a little more clear now. I'm going to go study until my eyes water and/or begin to blur. Any study tips to offer?
 
  • #16
kaylanp01 said:
Okay, its a little more clear now. I'm going to go study until my eyes water and/or begin to blur. Any study tips to offer?

Next term read ahead before the lectures.
 
  • #17
LowlyPion said:
Next term read ahead before the lectures.
Thankfully, I won't be doing another physics course after this term. I usually read ahead throughout the semester, but really got off track within the past few weeks. Luckily, I currently have an A, so I can afford to do not-so-well on the final. ha.
 
  • #18
Good luck on the exam then.

Cheers.
 
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