Merry-go-round with brick and sliding friction.

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SUMMARY

The discussion centers on a physics problem involving a rotating merry-go-round platform with a radius of 2.0 meters and a moment of inertia of 200 kg m². A 50 kg brick is placed on the platform, initially at 0.5 meters from the axis, and slides until it reaches 1.0 meter. The conservation of angular momentum is applied to determine the final angular velocity, which is calculated to be 0.85 rad/s. The mechanical energy converted to heat due to friction is determined to be 15.94 Joules.

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Homework Statement


The picture shows a rotating platform that serves as a playground
merry go round. The platform rotates on low-friction bearings about its center
axis. It has a radius of 2.0 meters, and its moment of inertia about the center
axis is 200 kg m2.

Suppose that the platform is given an initial rotation rate of 1.0 radians per
second. A small dense brick having a mass of 50 kg, initially at rest, is then
placed on the platform at a distance of 0.5 meters from the rotation axis. The
brick initially slides, but eventually stops sliding at a distance 1.0 m from the
axis. How many Joules of mechanical energy are converted to heat?

Homework Equations


I_{brick}=mr^{2}

L_{i}=L_{f}=>I_{i}\omega_{i}=I_{f}\omega_{f} (cons. of angular momentum)

ΔK=-fx +W_{ext} (work-energy theorem)

The Attempt at a Solution


I_{brick i}=(50kg)(0.25m^{2})=12.5kg.m^{2}

I_{brick f}=(50kg)(1m^{2})=50kg.m^{2}

I_{i}=I_{disk i}+I_{brick i}=212.5kg.m^{2}

I_{f}=I_{disk f}+I_{brick f}=250kg.m^{2}

\omega_{f}=\frac{I_{i}}{I_{f}}\omega_{i}=0.85\frac{rad}{s}

ΔK=-fx (no external work, just friction)

\frac{1}{2}I_{i}\omega_{i}^{2}-\frac{1}{2}I_{f}\omega_{f}^{2}=15.94 J

Just wondering if my solution method is looking ok. Thanks for the help!
 
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AbigailM said:


Suppose that the platform is given an initial rotation rate of 1.0 radians per
second. A small dense brick having a mass of 50 kg, initially at rest, is then
placed on the platform at a distance of 0.5 meters from the rotation axis. The
brick initially slides, but eventually stops sliding at a distance 1.0 m from the
axis.


The wording here might be open to interpretation. I'm thinking that the brick is initially at rest with respect to the Earth when it is let go at 0.5 m from the axis. It is therefore slipping on the platform until friction finally brings it to rest relative to the platform at 1.0 m from the axis. If so, would the brick contribute to the initial angular momentum?
 

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