Mesh Current Analysis w/ Controlled Current Source

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SUMMARY

The discussion focuses on solving for the mesh current i_x in a circuit analysis problem using mesh current analysis with a controlled current source. The user defined three mesh currents: i1 for the lower left loop, i2 for the lower right loop, and i3 for the upper loop. The equations derived from the mesh analysis were i1 = 2i_x, -10 + 3(i2 - i3) + 20i2 = 0, and -5 + 3(i3 - i2) + 10(i3 - i1) = 0. The user concluded with values i1 = 0, i2 = 0.5, and i3 = 0.5, questioning the validity of i1 being zero, to which another participant confirmed that this result is acceptable.

PREREQUISITES
  • Understanding of mesh current analysis in electrical circuits
  • Familiarity with controlled current sources
  • Basic knowledge of circuit equations and algebra
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Study the principles of mesh current analysis in greater detail
  • Learn about controlled current sources and their applications in circuit design
  • Practice solving complex circuit problems using mesh analysis
  • Explore the implications of zero current in circuit analysis and its physical significance
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing electrical circuits using mesh current analysis.

zarrin77
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Solve i_x when a=2. (See attached picture)

This is my attempt (mesh current analysis):

I made i1 be the lower left loop current.
I made i2 be the lower right loop current.
I made i3 be the upper loop current.

Mesh1: i1 = 2ix

Mesh2: -10 + 3(i2-i3) + 20i2 = 0

Mesh3: -5 + 3(i3 - i2) + 10(i3-i1) = 0

Also: ix = i3 - i2 => -i1 - 2i2 + 2i3 = 0


Using those last three equations: i1=0, i2=.5, i3=.5

I don't think that i1 can be 0... and I can't figure out any place I went wrong; it seems pretty straightforward?

Thank you very much for your help!
 

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zarrin77 said:
Solve i_x when a=2. (See attached picture)

This is my attempt (mesh current analysis):

I made i1 be the lower left loop current.
I made i2 be the lower right loop current.
I made i3 be the upper loop current.

Mesh1: i1 = 2ix

Mesh2: -10 + 3(i2-i3) + 20i2 = 0

Mesh3: -5 + 3(i3 - i2) + 10(i3-i1) = 0

Also: ix = i3 - i2 => -i1 - 2i2 + 2i3 = 0


Using those last three equations: i1=0, i2=.5, i3=.5

I don't think that i1 can be 0... and I can't figure out any place I went wrong; it seems pretty straightforward?

Thank you very much for your help!

There's no reason why i1 (and hence Ix) cannot be zero. Your solution looks okay to me.
 

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